x^2+0.0392x-0.044=0

Solution for x^2+0.0392x-0.044=0 equation:

x^2+0.0392x-0.044=0

a = 1; b = 0.0392; c = -0.044;
Δ = b2-4ac
Δ = 0.03922-4·1·(-0.044)
Δ = 0.17753664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0392)-\sqrt{0.17753664}}{2*1}=\frac{-0.0392-\sqrt{0.17753664}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0392)+\sqrt{0.17753664}}{2*1}=\frac{-0.0392+\sqrt{0.17753664}}{2}
$